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- /* log1p(x) = log(1+x). The log1p function is designed to avoid the
- significant loss of precision that arises from direct evaluation when x is
- small. Use the substitute from _math.h on all platforms: it includes
- workarounds for buggy handling of zeros.
- */
- static double
- _Py_log1p(double x)
- {
- /* Some platforms (e.g. MacOS X 10.8, see gh-59682) supply a log1p function
- but don't respect the sign of zero: log1p(-0.0) gives 0.0 instead of
- the correct result of -0.0.
- To save fiddling with configure tests and platform checks, we handle the
- special case of zero input directly on all platforms.
- */
- if (x == 0.0) {
- return x;
- }
- else {
- return log1p(x);
- }
- }
- #define m_log1p _Py_log1p
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