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- /*
- * Copyright Amazon.com, Inc. or its affiliates. All Rights Reserved.
- *
- * Licensed under the Apache License, Version 2.0 (the "License").
- * You may not use this file except in compliance with the License.
- * A copy of the License is located at
- *
- * http://aws.amazon.com/apache2.0
- *
- * or in the "license" file accompanying this file. This file is distributed
- * on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either
- * express or implied. See the License for the specific language governing
- * permissions and limitations under the License.
- */
- #include "utils/s2n_rfc5952.h"
- #include <stdio.h>
- #include <sys/socket.h>
- #include <sys/types.h>
- #include "error/s2n_errno.h"
- #include "utils/s2n_safety.h"
- static uint8_t dec[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' };
- static uint8_t hex[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f' };
- S2N_RESULT s2n_inet_ntop(int af, const void *addr, struct s2n_blob *dst)
- {
- const uint8_t *bytes = addr;
- uint8_t *cursor = dst->data;
- if (af == AF_INET) {
- RESULT_ENSURE(dst->size >= sizeof("111.222.333.444"), S2N_ERR_SIZE_MISMATCH);
- for (int i = 0; i < 4; i++) {
- if (bytes[i] / 100) {
- *cursor++ = dec[bytes[i] / 100];
- }
- if (bytes[i] >= 10) {
- *cursor++ = dec[(bytes[i] % 100) / 10];
- }
- *cursor++ = dec[(bytes[i] % 10)];
- *cursor++ = '.';
- }
- *--cursor = '\0';
- return S2N_RESULT_OK;
- }
- if (af == AF_INET6) {
- RESULT_ENSURE(dst->size >= sizeof("1111:2222:3333:4444:5555:6666:7777:8888"), S2N_ERR_SIZE_MISMATCH);
- /* See Section 4 of RFC5952 for the rules we are going to follow here
- *
- * Here's the general algorithm:
- *
- * 1/ Treat the bytes as 8 16-bit fields
- * 2/ Find the longest run of 16-bit fields.
- * 3/ or if there are two or more equal length longest runs, go with the left-most run
- * 4/ Make that run ::
- * 5/ Print the remaining 16-bit fields in lowercase hex, no leading zeroes
- */
- uint16_t octets[8] = { 0 };
- int longest_run_start = 0;
- int longest_run_length = 0;
- int current_run_length = 0;
- /* 2001:db8::1:0:0:1 */
- /* Find the longest run of zeroes */
- for (int i = 0; i < 8; i++) {
- octets[i] = (bytes[i * 2] << 8) + bytes[(i * 2) + 1];
- if (octets[i]) {
- current_run_length = 0;
- } else {
- current_run_length++;
- }
- if (current_run_length > longest_run_length) {
- longest_run_length = current_run_length;
- longest_run_start = (i - current_run_length) + 1;
- }
- }
- for (int i = 0; i < 8; i++) {
- if (i == longest_run_start && longest_run_length > 1) {
- if (i == 0) {
- *cursor++ = ':';
- }
- if (longest_run_length == 8) {
- *cursor++ = ':';
- }
- i += longest_run_length - 1;
- } else {
- uint8_t nibbles[4] = { (octets[i] & 0xF000) >> 12,
- (octets[i] & 0x0F00) >> 8,
- (octets[i] & 0x00F0) >> 4,
- (octets[i] & 0x000F) };
- /* Skip up to three leading zeroes */
- int j;
- for (j = 0; j < 3; j++) {
- if (nibbles[j]) {
- break;
- }
- }
- for (; j < 4; j++) {
- *cursor++ = hex[nibbles[j]];
- }
- }
- *cursor++ = ':';
- }
- *--cursor = '\0';
- return S2N_RESULT_OK;
- }
- RESULT_BAIL(S2N_ERR_INVALID_ARGUMENT);
- }
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