ydb/yql/essentials/tests/postgresql/original/cases/select_having.out

--
-- SELECT_HAVING
--
-- load test data
CREATE TABLE test_having (a int, b int, c char(8), d char);
INSERT INTO test_having VALUES (0, 1, 'XXXX', 'A');
INSERT INTO test_having VALUES (1, 2, 'AAAA', 'b');
INSERT INTO test_having VALUES (2, 2, 'AAAA', 'c');
INSERT INTO test_having VALUES (3, 3, 'BBBB', 'D');
INSERT INTO test_having VALUES (4, 3, 'BBBB', 'e');
INSERT INTO test_having VALUES (5, 3, 'bbbb', 'F');
INSERT INTO test_having VALUES (6, 4, 'cccc', 'g');
INSERT INTO test_having VALUES (7, 4, 'cccc', 'h');
INSERT INTO test_having VALUES (8, 4, 'CCCC', 'I');
INSERT INTO test_having VALUES (9, 4, 'CCCC', 'j');
SELECT b, c FROM test_having
	GROUP BY b, c HAVING count(*) = 1 ORDER BY b, c;
 b |    c     
---+----------
 1 | XXXX    
 3 | bbbb    
(2 rows)

-- HAVING is effectively equivalent to WHERE in this case
SELECT b, c FROM test_having
	GROUP BY b, c HAVING b = 3 ORDER BY b, c;
 b |    c     
---+----------
 3 | BBBB    
 3 | bbbb    
(2 rows)

SELECT lower(c), count(c) FROM test_having
	GROUP BY lower(c) HAVING count(*) > 2 OR min(a) = max(a)
	ORDER BY lower(c);
 lower | count 
-------+-------
 bbbb  |     3
 cccc  |     4
 xxxx  |     1
(3 rows)

SELECT c, max(a) FROM test_having
	GROUP BY c HAVING count(*) > 2 OR min(a) = max(a)
	ORDER BY c;
    c     | max 
----------+-----
 XXXX     |   0
 bbbb     |   5
(2 rows)

-- test degenerate cases involving HAVING without GROUP BY
-- Per SQL spec, these should generate 0 or 1 row, even without aggregates
SELECT min(a), max(a) FROM test_having HAVING min(a) = max(a);
 min | max 
-----+-----
(0 rows)

SELECT min(a), max(a) FROM test_having HAVING min(a) < max(a);
 min | max 
-----+-----
   0 |   9
(1 row)

-- errors: ungrouped column references
SELECT a FROM test_having HAVING min(a) < max(a);
ERROR:  column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT a FROM test_having HAVING min(a) < max(a);
               ^
SELECT 1 AS one FROM test_having HAVING a > 1;
ERROR:  column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT 1 AS one FROM test_having HAVING a > 1;
                                                ^
-- the really degenerate case: need not scan table at all
SELECT 1 AS one FROM test_having HAVING 1 > 2;
 one 
-----
(0 rows)

SELECT 1 AS one FROM test_having HAVING 1 < 2;
 one 
-----
   1
(1 row)

-- and just to prove that we aren't scanning the table:
SELECT 1 AS one FROM test_having WHERE 1/a = 1 HAVING 1 < 2;
 one 
-----
   1
(1 row)

DROP TABLE test_having;